Row 3899

Row ID: 3899 | Dataset Entry | Axioma AXP Content Repository

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Can anybody explain me how infinite lattice systems are easier to solve than finite systems with boundary conditions. And if it is because of the transverse invariant conditions and symmetries assumed then wouldn’t it introduce extra errors.

FieldValue
text Can anybody explain me how infinite lattice systems are easier to solve than finite systems with boundary conditions. And if it is because of the transverse invariant conditions and symmetries assumed then wouldn’t it introduce extra errors.
label r/quantumcomputing
dataType post
communityName r/QuantumComputing
datetime 2024-03-28
username_encoded Z0FBQUFBQm5LakwxbUVRLUN2MURfN1lUbXJoTkU3SWNyX1ZCTkRlN2QzUGZ2TW5oRUt0dUx3U0hQWC0xV2dvTTBHaEszRnZlcm9MZUlydExJUHlBU25HLXM2TUVkendtM1E9PQ==
url_encoded Z0FBQUFBQm5Lak9FdjIzU2FfcUZyQmRNaUVsSkh5SV9qSGdJcFp4cHJmdmhFNGVMYXZ6NUNPMThPc3dSQ2pVUFVqaWJwOWd0TWNmZEFEQTA1bm0tclJlMV9BTG9vSlI2QmhaMkxiYVR1RXBSeUxjYXhYN01iRFNkM0g4bzd3NHhmS0lLeFZRRW9VNU5veGVqcm9FOVZoUEdCZ1dRWTZxcC1zVW5EdVJZdkFUYmt3RUhnUkZzNHB4TFlSal8xOEFJWTcyZ0JiREFjaHRJZ21jdWhTMmowenZOYXdQbHNnc3F4UT09

Raw Record

{
  "text": "Can anybody explain me how infinite lattice systems are easier to solve than finite systems with boundary conditions. And if it is because of the transverse invariant conditions and symmetries assumed then wouldn’t it introduce extra errors.",
  "label": "r/quantumcomputing",
  "dataType": "post",
  "communityName": "r/QuantumComputing",
  "datetime": "2024-03-28",
  "username_encoded": "Z0FBQUFBQm5LakwxbUVRLUN2MURfN1lUbXJoTkU3SWNyX1ZCTkRlN2QzUGZ2TW5oRUt0dUx3U0hQWC0xV2dvTTBHaEszRnZlcm9MZUlydExJUHlBU25HLXM2TUVkendtM1E9PQ==",
  "url_encoded": "Z0FBQUFBQm5Lak9FdjIzU2FfcUZyQmRNaUVsSkh5SV9qSGdJcFp4cHJmdmhFNGVMYXZ6NUNPMThPc3dSQ2pVUFVqaWJwOWd0TWNmZEFEQTA1bm0tclJlMV9BTG9vSlI2QmhaMkxiYVR1RXBSeUxjYXhYN01iRFNkM0g4bzd3NHhmS0lLeFZRRW9VNU5veGVqcm9FOVZoUEdCZ1dRWTZxcC1zVW5EdVJZdkFUYmt3RUhnUkZzNHB4TFlSal8xOEFJWTcyZ0JiREFjaHRJZ21jdWhTMmowenZOYXdQbHNnc3F4UT09"
}
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